Set $ g'(s) = 0 \Rightarrow 2 = \frac{1}{s^2} \Rightarrow s^2 = \frac{1}{2} \Rightarrow s = \frac{1}{\sqrt{2}} \approx 0.707 > \frac{1}{2} $, not in domain.

Thu, 07 May 2026 12:55:06 +0000

Content under review