The area of the original equilateral triangle is \( A_1 = \frac{\sqrt{3}}{4} s^2 \). The area of the smaller equilateral triangle with side \( \frac{s}{2} \) is \( A_2 = \frac{\sqrt{3}}{4} \left(\frac{s}{2}\right)^2 = \frac{\sqrt{3}}{4} \cdot \frac{s^2}{4} = \frac{\sqrt{3}}{16} s^2 \). The decrease in area is \( \Delta A = A_1 - A_2 = \frac{\sqrt{3}}{4} s^2 - \frac{\sqrt{3}}{16} s^2 = \left(\frac{4}{16} - \frac{1}{16}\right)\sqrt{3} s^2 = \frac{3\sqrt{3}}{16} s^2 \). The percentage decrease is:

Sat, 09 May 2026 04:03:02 +0000

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